-5f^2+5f-1=0

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Solution for -5f^2+5f-1=0 equation: 



-5f^2+5f-1=0

a = -5; b = 5; c = -1;
Δ = b2-4ac
Δ = 52-4·(-5)·(-1)
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{5}}{2*-5}=\frac{-5-\sqrt{5}}{-10}
$


$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{5}}{2*-5}=\frac{-5+\sqrt{5}}{-10}
$

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